In a class of $ 60 $ students, $ 25 $ students play cricket and $ 20 $ students play tennis and $ 10 $ students play both the games, then the number of students who play neither is

Question

In a class of $ 60 $ students, $ 25 $ students play cricket and $ 20 $ students play tennis and $ 10 $ students play both the games, then the number of students who play neither is, $ 45 $, $ 0 $, $ 25 $, $ 35 $

MARKS App · Accepted Answer

Let student play cricket = C Student play tennis = T and total number of students = S ∴ n S = 60 , n C = 25 , n T = 20 and n C ∩ T = 10 Now, n C ∪ T = n C + n T - n C ∩ T = 25 + 20 - 10 = 35 ∴ The number of students who play neither game = n C ∩ T ′ = n S - n C ∪ T = 60 - 35 = 25

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