In a closed vessel a mixture of two moles of carbon monoxide and one mole of oxygen is ignited to convert the carbon monoxide to carbon dioxide. If Δ H is the enthalpy change and Δ E is the change in internal energy, then

Question

In a closed vessel a mixture of two moles of carbon monoxide and one mole of oxygen is ignited to convert the carbon monoxide to carbon dioxide. If Δ H is the enthalpy change and Δ E is the change in internal energy, then, Δ H = Δ E, Δ H > Δ E, Δ H Δ E, The relationship depends on the capacity of the vessel

MARKS App · Accepted Answer

Formation of C O 2 from C O is an exothermic reaction; heat is evolved from the system, i.e., energy is lowered. Thus, exothermic reactions occur spontaneously on account of decrease in enthapy of system. Thus, Δ E > Δ H .

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