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In a closed vessel, an ideal gas at $1 \mathrm{~atm}$ is heated from $27^{\circ} \mathrm{C}$ to $327^{\circ} \mathrm{C}$. the final pressure of the gas wil approximately be
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2 atm
$\mathrm{P} \propto \mathrm{T}(\mathrm{V}, \mathrm{n} \rightarrow$ const $)$
$\frac{\mathrm{P}_{1}}{\mathrm{P}_{2}}=\frac{\mathrm{T}_{1}}{\mathrm{~T}_{2}}$
$\frac{1}{\mathrm{P}_{2}}=\frac{300}{600}$
$\mathrm{P}_{2}=2 \mathrm{~atm}$
$\frac{\mathrm{P}_{1}}{\mathrm{P}_{2}}=\frac{\mathrm{T}_{1}}{\mathrm{~T}_{2}}$
$\frac{1}{\mathrm{P}_{2}}=\frac{300}{600}$
$\mathrm{P}_{2}=2 \mathrm{~atm}$
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