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In a closed vesselat STP, 50 L of $\mathrm{CH}_{4}$ is ignited with $750 \mathrm{~L}$ of air (containing $\left.20 \% \mathrm{O}_{2}\right)$. The number of moles of $\mathrm{O}_{2}$ remaining in the vessel on cooling to room temperature is closest to
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The correct answer is:
$2.2$
$\begin{array}{l}
\mathrm{CH}_{4}+2 \mathrm{O}_{2} \longrightarrow \mathrm{CO}_{2}+2 \mathrm{H}_{2} \mathrm{O} \\
50 \mathrm{~L} \quad 150 \mathrm{~L}
\end{array}$
$\mathrm{CH}_{4}$ is limiting reagent
Moles of $\mathrm{O}_{2}$ remaining $=\frac{50}{22.4}=2.2$ moles
\mathrm{CH}_{4}+2 \mathrm{O}_{2} \longrightarrow \mathrm{CO}_{2}+2 \mathrm{H}_{2} \mathrm{O} \\
50 \mathrm{~L} \quad 150 \mathrm{~L}
\end{array}$
$\mathrm{CH}_{4}$ is limiting reagent
Moles of $\mathrm{O}_{2}$ remaining $=\frac{50}{22.4}=2.2$ moles
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