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In a close-packed body-centred cubic lattice of potassium, the correct relation between the atomic radius $(r)$ of potassium and the edge-length of the cube is
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The correct answer is:
$r=\frac{\sqrt{3}}{4} a$
$\because$ For be packing, $\sqrt{3} a=4 r \therefore r=\frac{\sqrt{3}}{4} \cdot a$
where $a=$ edge length $r=$ radius of lattice sphere
where $a=$ edge length $r=$ radius of lattice sphere
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