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In a co-axial straight cable, the central conductor and the outer conductor carry equal currents in opposite directions. The magnetic field is zero :
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The correct answer is:
outside the cable
$\oint \overrightarrow{\mathrm{B}} \cdot \mathrm{d} \vec{\ell}=\mu_0 \mathrm{i}_{\mathrm{enc}}=0$
$\therefore \mathrm{B}=0$ outside the cable
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