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In a coil of resistance $10 \Omega$, the induced current developed by changing magnetic flux through it, is shown in figure as a function of time. The magnitude of change in flux through the coil in weber is
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The correct answer is:
2
$$
\begin{aligned}
I & =\left|\frac{1}{R} \frac{d \phi}{d t}\right| \\
|d \phi| & =|I R d t| \\
d \phi & =(\text { area of triangle }) \times R \\
& =\left(\frac{1}{2} \times 4 \times 0.1\right) \times 10=2 \mathrm{~Wb}
\end{aligned}
$$
\begin{aligned}
I & =\left|\frac{1}{R} \frac{d \phi}{d t}\right| \\
|d \phi| & =|I R d t| \\
d \phi & =(\text { area of triangle }) \times R \\
& =\left(\frac{1}{2} \times 4 \times 0.1\right) \times 10=2 \mathrm{~Wb}
\end{aligned}
$$
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