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In a common base mode of a transistor, the collector current is $5.488 \mathrm{~mA}$ for an emitter current of $5.60 \mathrm{~mA}$. The value of the base current amplification factor $(\beta)$ will be
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The correct answer is:
49
$$
\mathrm{I}_{\mathrm{c}}=5.488 \mathrm{~mA}, \mathrm{I}_{\mathrm{e}}=5.6 \mathrm{~mA}
$$
$$
\alpha=\frac{\mathrm{I}_{\mathrm{c}}}{\mathrm{I}_{\mathrm{e}}}
$$
$$
\alpha=\frac{5.488}{5.6}
$$
$$
\beta=\frac{\alpha}{(1-\alpha)}=49
$$
\mathrm{I}_{\mathrm{c}}=5.488 \mathrm{~mA}, \mathrm{I}_{\mathrm{e}}=5.6 \mathrm{~mA}
$$
$$
\alpha=\frac{\mathrm{I}_{\mathrm{c}}}{\mathrm{I}_{\mathrm{e}}}
$$
$$
\alpha=\frac{5.488}{5.6}
$$
$$
\beta=\frac{\alpha}{(1-\alpha)}=49
$$
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