Search any question & find its solution
Question:
Answered & Verified by Expert
In a common emitter transistor amplifier $\beta=60$, $\mathrm{R}_{\mathrm{o}}=5000 \Omega$ and internal resistance of a transistor is $500 \Omega$. The voltage amplification of amplifier will be
Options:
Solution:
1091 Upvotes
Verified Answer
The correct answer is:
600
Voltage amplification
$$
A_{\mathrm{V}}=\beta \frac{\mathrm{R}_{\mathrm{o}}}{\mathrm{R}_{\mathrm{i}}}=60 \times \frac{5000}{500}=600
$$
$$
A_{\mathrm{V}}=\beta \frac{\mathrm{R}_{\mathrm{o}}}{\mathrm{R}_{\mathrm{i}}}=60 \times \frac{5000}{500}=600
$$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.