In a common-emitter configuration of a transistor, the base current I E = 2 μ A , α = 0.9 then the value of I C is

Question

In a common-emitter configuration of a transistor, the base current I E = 2 μ A , α = 0.9 then the value of I C is, 3 . 0 μ A, 2 . 25 μ A, 4 . 9 μ A, 1 . 8 μ A

MARKS App · Accepted Answer

We know that current gain is given by, α = I c I b ∴ I c = α × I b = 0.9 × 2 = 1.8 μ A

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