In a common-emitter transistor amplifier, the output resistance is 500 kΩ and the current gain β = 49 . If the power gain of the amplifier is 5 × 10 6 , the input resistance is

Question

In a common-emitter transistor amplifier, the output resistance is 500 kΩ and the current gain β = 49 . If the power gain of the amplifier is 5 × 10 6 , the input resistance is, 165 Ω, 198 Ω, 225 Ω, 240 Ω

MARKS App · Accepted Answer

Given, R o = 500 kΩ , β = 49 and P = 5 × 10 6 We have P = β 2 R o R i 5 × 10 6 = 49 2 × 500 × 10 3 R i R i = 49 × 49 × 500 × 10 3 5 × 10 6 = 240 Ω

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