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In a compound atoms of element $Y$ from ccp lattice and those of element $X$ occupy $2 / 3^{\text {rd }}$ of tetrahedral voids. The formula of the compound will be
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The correct answer is:
$X_4 Y_3$
$X_4 Y_3$
No. of atoms of $Y=4$
No. of atoms of $X=\frac{2}{3} \times 8$
Formula of compound will be $X_4 Y_3$
No. of atoms of $X=\frac{2}{3} \times 8$
Formula of compound will be $X_4 Y_3$
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