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Question: Answered & Verified by Expert
In a constant volume calorimeter, 3.5 g of a gas with molecular weight 28 was burnt in excess oxygen at 298.0 K. The temperature of the calorimeter was found to increase from 298.0 K to 298.45 K due to the combustion process. Given that the heat capacity of the calorimeter is 2.5 kJ K-1 , the numerical value for the enthalpy of combustion of the gas in kJ mol-1 is
ChemistryThermodynamics (C)JEE Main
Solution:
2674 Upvotes Verified Answer
The correct answer is: 9
Energy released by combustion of 3.5 g gas

=2.5×(298.45-298)kJ

Energy released by 1 mole of gas =2.5×0.453.528=9 kJmol-1

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