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In a crossed field, the magnetic field induction is $2.0 \mathrm{~T}$ and electric field intensity is $20 \times 10^3 \mathrm{~V} / \mathrm{m}$. At which velocity the electron will travel in a straight line without the effect of electric and magnetic fields?
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The correct answer is:
$10 \times\ 10^3\ ms^{-1}$
$e V B=e E$
where, $e=$ electronic charge and $v=$ velocity of electron
$\Rightarrow \quad v=\frac{E}{B} v=\frac{20 \times 10^3}{2.0}=10 \times 10^3 \mathrm{~ms}^{-1}$
where, $e=$ electronic charge and $v=$ velocity of electron
$\Rightarrow \quad v=\frac{E}{B} v=\frac{20 \times 10^3}{2.0}=10 \times 10^3 \mathrm{~ms}^{-1}$
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