In a cubic packed structure of mixed oxides, the lattice is made up of oxide ions, one fifth of tetrahedral voids one occupied by X ions while one half of the octahedral voids are occupied by Y ions. Then formula of the oxide will be

Question

In a cubic packed structure of mixed oxides, the lattice is made up of oxide ions, one fifth of tetrahedral voids one occupied by X ions while one half of the octahedral voids are occupied by Y ions. Then formula of the oxide will be, X 5 Y 4 O 10, X 4 Y 5 O 10, X Y 2 O 4, X 2 Y O 4

MARKS App · Accepted Answer

Number of O 2 - ions = n Number of tetrahedral voids = 2n Number of octahedral voids = n Number of X ions = 2 n 5 Number of Y ions = n 2 X : Y : O 2n 5 : n 2 : n 4 : 5 : 10 Simplest formula = X 4 Y 5 O 10 .

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