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In a cuboid of dimension $2 \mathrm{~L} \times 2 \mathrm{~L} \times \mathrm{L}$, a charge $q$ is placed at the centre of the surface ' $S$ ' having area of $4 \mathrm{~L}^2$. The flux through the opposite surface to ' $\mathrm{S}$ ' is given by
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The correct answer is:
$\frac{q}{6 \varepsilon_0}$
After placing similar cubic at the bottom, we get cube of side $2 \mathrm{~L}$ having change $\mathrm{q}$ at its centre.
From the Gauss's law electric flux through whole
Flux passing through shaded face
$\phi=\frac{\mathrm{q} / \varepsilon_0}{6}=\frac{\mathrm{q}}{6 \varepsilon_0}$
From the Gauss's law electric flux through whole
Flux passing through shaded face
$\phi=\frac{\mathrm{q} / \varepsilon_0}{6}=\frac{\mathrm{q}}{6 \varepsilon_0}$
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