In a diode, the diffusion current is $ i_{i f f u s i o n} $ and drift current is $ i_{i d i f i t} $, then match the column. $\begin{array}{|l|l|} \hline \text{Column-I} & \text{Column-II} \ \hline \text{(1) Diode with no biasing} & (p) \mathrm{i}_{\text {diffusion }}\mathrm{i}_{\text {drift }} \ \text{(2) Diode in forward bias} & \text{(q) } \mathrm{i}_{\text {drift }} \mathrm{i}_{\text {diffusion }} \ \text{(3) Diode in reverse bias without} & (r) \dot{\mathrm{I}}_{\mathrm{drift}} \mathrm{i}_{\text {diffusion }} \ \text{breakdown} & \ \text{(4) Diode in reverse bias with} & (s) \dot{\mathrm{I}}_{\mathrm{drift}}=\mathrm{i}_{\text {diffusion }}\ \text{breakdown} & \ \hline \end{array}$

Question

In a diode, the diffusion current is $ i_{i f f u s i o n} $ and drift current is $ i_{i d i f i t} $, then match the column. $\begin{array}{|l|l|} \hline \text{Column-I} & \text{Column-II} \ \hline \text{(1) Diode with no biasing} & (p) \mathrm{i}_{\text {diffusion }}>>\mathrm{i}_{\text {drift }} \ \text{(2) Diode in forward bias} & \text{(q) } \mathrm{i}_{\text {drift }}> >\mathrm{i}_{\text {diffusion }} \ \text{(3) Diode in reverse bias without} & (r) \dot{\mathrm{I}}_{\mathrm{drift}} >\mathrm{i}_{\text {diffusion }} \ \text{breakdown} & \ \text{(4) Diode in reverse bias with} & (s) \dot{\mathrm{I}}_{\mathrm{drift}}=\mathrm{i}_{\text {diffusion }}\ \text{breakdown} & \ \hline \end{array}$, $ A \rightarrow s, B \rightarrow q, C \rightarrow r, D \rightarrow p $, $ A \rightarrow s, B \rightarrow p, C \rightarrow r, D \rightarrow q $, $ A \rightarrow s, B \rightarrow q, C \rightarrow p, D \rightarrow r $, $ A \rightarrow q, B \rightarrow p, C \rightarrow r, D \rightarrow s $

MARKS App · Accepted Answer

Diode with no biasing ⇒ I drift = i diffusion Diode in forward bias ⇒ İ d i f f u s i o n > > i d r i f t Diode in reverse bias without breakdown ⇒ İ d r i f t > i d i f f u s i o n Diode in reverse bias with breakdown ⇒ i d r i f t > > i d i f f u s i o n

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