Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
In a double slit experiment with monochromatic light, fringes are obtained on a screen placed at some distance from the plane of slits. If the screen is moved by 5×10-2 m towards the slits, the change in fringe width is 3×10-3 cm. If the distance between the slits is 1 mm, then the wavelength of the light will be____nm.
PhysicsWave OpticsJEE MainJEE Main 2022 (29 Jun Shift 2)
Solution:
1914 Upvotes Verified Answer
The correct answer is: 600

We know that the fringe width in YDSE is β=λDd

Δβ=λdΔD

λ=ΔβdΔD=3×10-3×10-2×10-35×10-2=6×10-7 m=600 nm

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.