In a double-slit experiment, the two slits are 1 mm apart and the screen is placed 1 m away. A monochromatic light of wavelength 500 nm is used. What will be the width of each slit for obtaining ten maxima of double-slit within the central maxima of a single-slit pattern?

Question

In a double-slit experiment, the two slits are 1 mm apart and the screen is placed 1 m away. A monochromatic light of wavelength 500 nm is used. What will be the width of each slit for obtaining ten maxima of double-slit within the central maxima of a single-slit pattern?, 0 . 2 mm, 0 . 1 mm, 0 . 5 mm, 0 . 02 mm

MARKS App · Accepted Answer

d = 1 mm = 1 × 10 - 3 m D = 1 m . , λ = 500 × 10 - 9 m Width of the central maximum = width of 10 maxima in YDSE 2 λ D a = 10 λ D d a = 0.2 d = 0 .2 mm

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