In a Fraunhoffer diffraction experiment at a single slit using light of wavelength 400 nm , the first minimum is formed at an angle of 30 ° . Then the direction θ of the first secondary maximum is

Question

In a Fraunhoffer diffraction experiment at a single slit using light of wavelength 400 nm , the first minimum is formed at an angle of 30 ° . Then the direction θ of the first secondary maximum is, tan - 1 ⁡ 4 3, 60 o, sin - 1 ⁡ 3 4, tan - 1 ⁡ 3 4

MARKS App · Accepted Answer

For first minimum, sin ⁡ 30 o = λ a 1 2 = λ a a = 2 λ Now, For 1st secondary maxima sin ⁡ θ = 3 λ 2 a sin ⁡ θ = 3 λ 2 × 2 λ sin ⁡ θ = 3 4 θ = sin - 1 ⁡ 3 4

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