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In a given network, each resistance has value of \(6 \Omega\). The point \(\mathrm{X}\) is connected to point \(\mathrm{A}\) by a copper wire of negligible resistance and point \(Y\) is connected to point B by the same wire. The effective resistance between \(\mathrm{X}\) and \(\mathrm{Y}\) will be
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Verified Answer
The correct answer is:
\(2 \Omega\)
One end of all the three resistors are connected at the point \(X\) and the other at the point \(Y\). Therefore, the equivalent circuit is given below:
The equivalent resistance is given by
\(\begin{aligned}
& \frac{1}{R}=\frac{1}{6}+\frac{1}{6}+\frac{1}{6}=\frac{3}{6}=\frac{1}{2} \\
& \Rightarrow R_{\text {eq }}=2 \Omega
\end{aligned}\)
The equivalent resistance is given by
\(\begin{aligned}
& \frac{1}{R}=\frac{1}{6}+\frac{1}{6}+\frac{1}{6}=\frac{3}{6}=\frac{1}{2} \\
& \Rightarrow R_{\text {eq }}=2 \Omega
\end{aligned}\)
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