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In a given network the equivalent capacitance between $A$ and $B$ is $C_{1}=C_{4}=1 \mu F, C_{2}=C_{3}=2 \mu F$.
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Verified Answer
The correct answer is:
$3 \mu \mathrm{F}$
The equivalent circuit is shown in figure.
$\mathrm{C}_{\mathrm{AB}}=1+\frac{2 \times 2}{2+2}+1$
$\mathrm{C}_{\mathrm{AB}}=3 \mu \mathrm{F}$
$\mathrm{C}_{\mathrm{AB}}=1+\frac{2 \times 2}{2+2}+1$
$\mathrm{C}_{\mathrm{AB}}=3 \mu \mathrm{F}$
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