In a hydraulic lift, compressed air exerts a force F on a small piston of radius 3 cm . Due to this pressure the second piston of radius 5 cm lifts a load of 1875 kg . The value of F is (Acceleration due to gravity = 10 m s - 2 )

Question

In a hydraulic lift, compressed air exerts a force F on a small piston of radius 3 cm . Due to this pressure the second piston of radius 5 cm lifts a load of 1875 kg . The value of F is (Acceleration due to gravity = 10 m s - 2 ), 1250 N, 125 N, 6750 N, 675 N

MARKS App · Accepted Answer

The principle for hydraulic lifts is based on Pascal's law. Pressure on both the piston will be same, F 1 A = F 2 A ⇒ F 1 π × 3 × 10 - 2 2 = F π × 5 × 10 - 2 2 ⇒ F 9 = 1875 × 10 25 ⇒ F = 6750 N

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