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In a junction transistor, the collector current changes by $6.8 \mathrm{~mA}$, if the emitter current is changed by $7 \mathrm{~mA}$. For such transistor, the current amplification factor is
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Given, $\Delta I_C=6.8 \mathrm{~mA}$
$$
\text { So, } \quad \begin{aligned}
\Delta I_E & =7 \mathrm{~mA} \\
\Delta I_B & =0.2 \mathrm{~mA}
\end{aligned}
$$
$\because$ Current amplification is $>1$
So, it must be $\mathrm{CE}$ configuration
Amplification factor, $\beta=\frac{\Delta I_C}{\Delta I_B}=\frac{6.8 \mathrm{~mA}}{0.2 \mathrm{~mA}}$
$$
\text { So, } \quad \begin{aligned}
\Delta I_E & =7 \mathrm{~mA} \\
\Delta I_B & =0.2 \mathrm{~mA}
\end{aligned}
$$
$\because$ Current amplification is $>1$
So, it must be $\mathrm{CE}$ configuration
Amplification factor, $\beta=\frac{\Delta I_C}{\Delta I_B}=\frac{6.8 \mathrm{~mA}}{0.2 \mathrm{~mA}}$
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