Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Open MARKS Web Download App
Search any question & find its solution
Question: Answered & Verified by Expert
In a Mendelian dihybrid cross, the probability of getting seeds with genotype Rryy, RrYy, rrYy and RrYY in F2 generation is respectively
BiologyPrinciples of Inheritance and VariationNEET
Options:
  • A 216 :416 :18 :18
  • B 216 :216 :216 :216
  • C 416 :416 :216 :216
  • D 18 :14 :28 :116
Solution:
1980 Upvotes Verified Answer
The correct answer is: 216 :416 :18 :18
In a Mendelian dihybrid cross, the genotypic ratio is RRYY:RrYY:RRYy:RrYy:rrYY:rrYy:RRyy:Rryy:rryy is 1:2:2:4:1:2:1:2:1. 

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.

Use on iOS or Desktop Download from Google Play