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In a mercury thermometer, the ice point (lower fixed point) is marked as $10^{\circ}$ and the steam point (upper fixed point) is marked as $130^{\circ}$. At $40^{\circ} \mathrm{C}$ temperature, what will this thermometer read?
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The correct answer is:
$58^{\circ}$
$\frac{x-10}{130-10}=\frac{40}{100}$
$$
\begin{array}{r}
100 x-1000=4800 \\
100 x=5800 \\
x=58^{\circ}
\end{array}
$$
$$
\begin{array}{r}
100 x-1000=4800 \\
100 x=5800 \\
x=58^{\circ}
\end{array}
$$
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