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In a meter bridge a copper coil is connected in the right gap and a resistance of $10 \Omega$ in the left gap. The balance point is obtained at $0.2 \mathrm{~m}$. The resistance of the coil is
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The correct answer is:
$40 \Omega$
Given, $P=10 \Omega, l=0.2 \mathrm{~m}$
In balanced condition of meterbridge,
$\frac{P}{Q}=\frac{l}{(1-\bar{l})}$
$\Rightarrow \quad \frac{10}{Q}=\frac{0.2}{1-0.2}=\frac{0.2}{0.8}$
$\Rightarrow \quad Q=40 \Omega$
In balanced condition of meterbridge,
$\frac{P}{Q}=\frac{l}{(1-\bar{l})}$
$\Rightarrow \quad \frac{10}{Q}=\frac{0.2}{1-0.2}=\frac{0.2}{0.8}$
$\Rightarrow \quad Q=40 \Omega$
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