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In a meter bridge the balancing length from the left end is found to be $25 \mathrm{~cm}$. The value of the unknown resistance is (assume, standard resistance of $1 \Omega$ is in the right gap)
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The correct answer is:
$0.33 \Omega$
According to given situation, circuit diagram of meter bridge is given as
At balance condition of meter bridge,
$\frac{S}{R}=\frac{25}{(100-25)} \Rightarrow \frac{S}{1}=\frac{25}{75} \Rightarrow S=\frac{1}{3} \Omega=0.33 \Omega$
At balance condition of meter bridge,
$\frac{S}{R}=\frac{25}{(100-25)} \Rightarrow \frac{S}{1}=\frac{25}{75} \Rightarrow S=\frac{1}{3} \Omega=0.33 \Omega$
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