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In a multi – electron atom, which of the following orbitals described by the three quantum numbers will have the same energy in the absence of magnetic acid and electric fields?
(a) $n=1, l=0, m=0$
(b) $n=2, l=0, m=0$
(c) $n=2, l=1, m=1$
(d) $n=3, l=2, m=1$
(e) $n=3, l=2, m=0$
Options:
(a) $n=1, l=0, m=0$
(b) $n=2, l=0, m=0$
(c) $n=2, l=1, m=1$
(d) $n=3, l=2, m=1$
(e) $n=3, l=2, m=0$
Solution:
1347 Upvotes
Verified Answer
The correct answer is:
(d) and (e)
(d) and (e)
n = same
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