Search any question & find its solution
Question:
Answered & Verified by Expert
In a non-leap year, the probability of getting 53 Sunday or 53 Tuesday or 53 Thursday is
Options:
Solution:
2997 Upvotes
Verified Answer
The correct answer is:
$\frac {3}{7}$
In non-leap year, there are 365 days i.e. 52 complete weeks and $1$ extra day.
That day can be any of 7 days.
$\therefore \quad P(53 \text { Sunday })=P(\text { Last } 1 \text { day Sunday })=\frac{1}{7}$
Similarly, $P(53$ Tuesday $)=\frac{1}{7}$
$\begin{aligned} & P(53 \text { Thursday })=\frac{1}{7} \\ & \therefore \quad \text { Probability }=\frac{1}{7}+\frac{1}{7}+\frac{1}{7}=\frac{3}{7} .\end{aligned}$
That day can be any of 7 days.
$\therefore \quad P(53 \text { Sunday })=P(\text { Last } 1 \text { day Sunday })=\frac{1}{7}$
Similarly, $P(53$ Tuesday $)=\frac{1}{7}$
$\begin{aligned} & P(53 \text { Thursday })=\frac{1}{7} \\ & \therefore \quad \text { Probability }=\frac{1}{7}+\frac{1}{7}+\frac{1}{7}=\frac{3}{7} .\end{aligned}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.