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In a non-leap year, the probability of having 53 Tuesday or 53 Wednesday is
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The correct answer is:
$\frac{2}{7}$
$\frac{2}{7}$
There are 365 days in a non-leap year i.e. 52 weeks and 1 day.
So, required probability of having 53 Tuesday or 53
Wednesday $=\frac{2}{7}$
So, required probability of having 53 Tuesday or 53
Wednesday $=\frac{2}{7}$
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