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In a nuclide, one a.m.u. of mass is dissipated into energy to bind its nucleons. The energy equivalent of this mass is
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The correct answer is:
$931.5 \times 10^6 \mathrm{eV}$
$\begin{aligned} & 1 \mathrm{amu}=1.492 \times 10^{-3} \mathrm{erg} \\ & 1 \mathrm{MeV}=10^6 \times 1.602 \times 10^{-12} \mathrm{erg} \\ & \therefore \quad 1 \mathrm{amu}=\frac{1.492 \times 10^{-3}}{1.602 \times 10^{-12} \times 10^6} \\ &=931.5 \mathrm{MeV} \\ & \therefore \quad 1 \mathrm{MeV}=10^6 \mathrm{eV} \\ & 1 \mathrm{amu}=931.5 \mathrm{MeV} \\ &=931.5 \times 10^6 \mathrm{eV}\end{aligned}$
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