Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
In a photoelectric experiment, the wavelength of the light incident on a metal is changed from 300 nm to 400 nm. Choose the closest value of change in the stopping potential from given options hce=1240 nm·V
PhysicsDual Nature of MatterJEE Main
Options:
  • A 2.0 V
  • B 0.5 V
  • C 1.0 V
  • D 1.5 V
Solution:
2835 Upvotes Verified Answer
The correct answer is: 1.0 V

vs1=1240300-ϕ 

vs2=1240400-ϕ

vs1-vs2=1240300-1240400

=4.13-3.1
=1.03
=1

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.