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In a plane electromagnetic wave, the maximum value of the electric field component is $4.4 \mathrm{Vm}^{-1}$. The intensity of the wave is nearly
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Verified Answer
The correct answer is:
$25.7 \mathrm{~mW} \mathrm{~m}^{-2}$
We know that
$\mathrm{I}=\frac{1}{2} \varepsilon_0 \mathrm{E}_0^2 \mathrm{C}$
$\begin{aligned} & =\frac{1}{2} \times 8.85 \times 10^{-12} \times 4.4^2 \times 3 \times 10^8 \\ & =25.7 \mathrm{~mW} / \mathrm{m}^2\end{aligned}$
$\mathrm{I}=\frac{1}{2} \varepsilon_0 \mathrm{E}_0^2 \mathrm{C}$
$\begin{aligned} & =\frac{1}{2} \times 8.85 \times 10^{-12} \times 4.4^2 \times 3 \times 10^8 \\ & =25.7 \mathrm{~mW} / \mathrm{m}^2\end{aligned}$
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