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In a population of 1000 individuals 360 belong to genotype AA, 480 to Aa, and the remaining 160 to aa, Based on this data, the frequency of allele A in the population is:
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The correct answer is:
According to HardyWeinberg principle:
Frequency of dominant allele (A) = p
Frequency of recessive allele (a) = q
Frequency of AA individuals = p × p = p2
Frequency of aa individuals = q × q = q2
Frequency of Aa individuals = 2pq
Total population = 1000
Frequency of AA individuals = p × p = p2 = 360/1000 = 0.36
Frequency of dominant allele (A) = p = 0.6
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