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In a potentiometer experiment, the balancing point with a cell is at a length \( 240 \mathrm{~cm} \). On
shunting the cell with a resistance of \( 2 \Omega \), the balancing length becomes \( 120 \mathrm{~cm} \). The internal
resistance of the cell is
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shunting the cell with a resistance of \( 2 \Omega \), the balancing length becomes \( 120 \mathrm{~cm} \). The internal
resistance of the cell is
Solution:
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Verified Answer
The correct answer is:
\( 2 \Omega \)
(D)
Internal resistance of a cell is \( R\left(\frac{l_{1}-l_{2}}{l_{2}}\right)=2\left(\frac{240-120}{120}\right)=2 \Omega \)
Internal resistance of a cell is \( R\left(\frac{l_{1}-l_{2}}{l_{2}}\right)=2\left(\frac{240-120}{120}\right)=2 \Omega \)
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