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In a potentiometer experiment, when a cell in the secondary circuit is shunted by a resistance ' $R$ ', balancing length is ' $L_1$ '. On doubling the shunt resistance, balancing length increases to ' $L_2$ '. Internal resistance of the cell is
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The correct answer is:
$\frac{2 \mathrm{R}\left(\mathrm{L}_2-\mathrm{L}_1\right)}{\left(2 \mathrm{~L}_1-\mathrm{L}_2\right)}$
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