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In a process, 701 J of heat is absorbed by a system and 394 J of work is done by the system. What is the change in internal energy (in J) for the process?
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Verified Answer
The correct answer is:
307.00
Given, q = + 701 J (heat is absorbed, heance q is positive.)
W = - 394 J (work is done by the system, hence W is negative.)
By first law of thermodynamics;
Internal energy change,
= + 701 J + (-394 J ) = + 307 J.
Hence, internal energy of the system increases by 307 J.
W = - 394 J (work is done by the system, hence W is negative.)
By first law of thermodynamics;
Internal energy change,
= + 701 J + (-394 J ) = + 307 J.
Hence, internal energy of the system increases by 307 J.
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