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In a process, a system performs $238 \mathrm{~J}$ of work on it's surrounding by absorbing $54 \mathrm{~J}$ of heat. What is the change in internal energy of system during this operation?
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Verified Answer
The correct answer is:
-184 J
Heat absorbed by the system is $(+)$ ve. Work done by the system is (-) ve.
$$
\begin{aligned}
& \mathrm{W}=-238 \mathrm{~J} \\
& \mathrm{q}=+54 \mathrm{~J} \\
& \Delta \mathrm{U}=\mathrm{q}+\mathrm{w} \\
& =54-238 \\
& =-184 \mathrm{~J}
\end{aligned}
$$
$$
\begin{aligned}
& \mathrm{W}=-238 \mathrm{~J} \\
& \mathrm{q}=+54 \mathrm{~J} \\
& \Delta \mathrm{U}=\mathrm{q}+\mathrm{w} \\
& =54-238 \\
& =-184 \mathrm{~J}
\end{aligned}
$$
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