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In a pure inductive circuit or In an ac circuit containing inductance only, the current
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The correct answer is:
Lags behind the e.m.f. by $90^{\circ}$
As we know,
In a pure inductor (zero resistance), voltage leads the current by $90^{\circ}$ i.e., $\frac{\pi}{2}$
In a pure inductor (zero resistance), voltage leads the current by $90^{\circ}$ i.e., $\frac{\pi}{2}$
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