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Question: Answered & Verified by Expert
In a quadrilateral $\mathrm{ABCD}$, which is not a trapezium, it is known that $\angle D A B=\angle A B C=60^{\circ}$. Moreover, $\angle C A B=\angle C B D$. Then.
MathematicsBasic of MathematicsKVPYKVPY 2014 (SA)
Options:
  • A $A B=B C+C D$
  • B $A B=A D+C D$
  • C $A B=B C+A D$
  • D $A B=A C+A D$
Solution:
2407 Upvotes Verified Answer
The correct answer is: $A B=A C+A D$
No Solution

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