In a radioactive material, the activity at time t 1 is R 1 and at a later time t 2 , it is R 2 . If the decay constant of the material is λ , then

Question

In a radioactive material, the activity at time t 1 is R 1 and at a later time t 2 , it is R 2 . If the decay constant of the material is λ , then, R 1 = R 2, R 1 = R 2 e − λ t 1 − t 2, R 1 = R 2 e λ t 1 − t 2, R 1 = R 2 t 2 / t 1

MARKS App · Accepted Answer

According to activity law, R = R 0 e –λt ∴ R 1 = R 0 e –λt 1 and R 2 = R 0 e –λt 2 ∴ R ⁡ 1 R ⁡ 2 = R ⁡ 0 e ⁡ - λ t 1 R ⁡ 0 e ⁡ - λ t 2 = e ⁡ - λ t 1 e ⁡ λ t 2 = e ⁡ - λ t 1 - t 2 or R 1 = R 2 e − λ t 1 − t 2

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