In a radioactive series, 92 238 U changes to 82 206 Pb through n 1 α decay process and n 2 β decay process, then

Question

In a radioactive series, 92 238 U changes to 82 206 Pb through n 1 α decay process and n 2 β decay process, then, n 1 = 8 , n 2 = 8, n 1 = 6 , n 2 = 6, n 1 = 8 , n 2 = 6, n 1 = 6 , n 2 = 8

MARKS App · Accepted Answer

92 238 U → 82 206 Pb + n 1 α + n 2 β From conservation of mass number: 238 = 206 + 4 n 1 32 = 4 n 1 ⇒ n 1 = 8 From conservation of charge: 92 = 82 + 2 n 1 - n 2 92 = 82 + 2 8 - n 2 ⇒ n 2 = 6

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