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Question: Answered & Verified by Expert
In a reactor, 2 kg of U23592 fuel is fully used up in 30 days. The energy released fission is 200 MeV. Given that the Avogadro number, N=6.023×1026 per kilo mole and 1 eV=1.6×10-19 J. The power output of the reactor is close to:
PhysicsWork Power EnergyJEE MainJEE Main 2020 (02 Sep Shift 1)
Options:
  • A 35 MW
  • B 60 MW
  • C 125 MW
  • D 54 MW
Solution:
2906 Upvotes Verified Answer
The correct answer is: 60 MW

P=Et

=2235×6.023×1026×200×1.6×10-1930×24×60×60=60 MW

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