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In a reverse biased diode when the applied voltage changes by $1 \mathrm{~V}$, the current is found to change by $0.5 \mu \mathrm{A}$. The reverse bias resistance of the diode is
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Verified Answer
The correct answer is:
$2 \times 10^{6} \Omega$
Reverse resistance
$$
\begin{aligned}
&=\frac{\Delta V}{\Delta I} \\
&=\frac{1}{0.5 \times 10^{-6}} \\
&=2 \times 10^{6} \Omega
\end{aligned}
$$
$$
\begin{aligned}
&=\frac{\Delta V}{\Delta I} \\
&=\frac{1}{0.5 \times 10^{-6}} \\
&=2 \times 10^{6} \Omega
\end{aligned}
$$
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