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In a right angle $\triangle \mathrm{ABC}, \angle \mathrm{A}=90^{\circ}$ and sides a, b, c are respectively, $5 \mathrm{~cm}, 4 \mathrm{~cm}$ and $3 \mathrm{~cm}$. If a force $\vec{F}$ has moments 0,9 and 16 in $N$ cm. units respectively about vertices $A, B$ and $C$, then magnitude of $\vec{F}$ is
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The correct answer is:
5
5
$\mathrm{F} \cdot 3 \sin \theta=9$
$\mathrm{~F} \cdot 4 \cos \theta=16$
$\Rightarrow \mathrm{F}=5$
$\mathrm{~F} \cdot 4 \cos \theta=16$
$\Rightarrow \mathrm{F}=5$
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