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In a rocket, fuel burns at the rate of \(1 \mathrm{~kg} / \mathrm{s}\). This fuel is ejected from the rocket with a velocity of \(60 \mathrm{~km} / \mathrm{s}\). The force exerted on the rocket by this is
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The correct answer is:
\(60000 \mathrm{~N}\)
For a rocket, \(\frac{d m}{d t}=1 \mathrm{~kg} / \mathrm{s}\)
Velocity of fuel ejected by rocket,
\(v=60 \mathrm{~km} / \mathrm{s}=60000 \mathrm{~m} / \mathrm{s}\)
\(\therefore\) Force exerted on the rocket is given as
\(F=v \frac{d m}{d t}=60000 \times 1=60000 \mathrm{~N}\)
Velocity of fuel ejected by rocket,
\(v=60 \mathrm{~km} / \mathrm{s}=60000 \mathrm{~m} / \mathrm{s}\)
\(\therefore\) Force exerted on the rocket is given as
\(F=v \frac{d m}{d t}=60000 \times 1=60000 \mathrm{~N}\)
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