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In a satellite if the time of revolution is $T$, then K.E. is proportional to
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The correct answer is:
$T^{-2 / 3}$
$V=\sqrt{\frac{G M}{r}} \quad \therefore \quad K . E . \propto v^2 \propto \frac{1}{r}$ and $T^2 \propto r^3$
$\therefore K . E . \propto T^{-2 / 3}$
$\therefore K . E . \propto T^{-2 / 3}$
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