In a series L C R circuit R = 300 Ω , L = 0.9 H , C = 2 µ F , ω = 1000 r a d / s . The impedance of the circuitis

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In a series

L C R

circuit

R = 300 Ω, L = 0.9 H, C = 2 µ F, ω = 1000 r a d / s .

The impedance of the circuitis

PhysicsAlternating CurrentMHT CETMHT CET 2019 (02 May Shift 1)

Options:

A $500 Ω$
B $1300 Ω$
C $400 Ω$
D $900 Ω$

Solution:

1509 Upvotes Verified Answer

The correct answer is:

500 Ω

Z = \sqrt{R^{2} + {(ω L - \frac{1}{ω C})}^{2}}

ω L = (1000) (0.9) = 900

\frac{1}{ω C} = \frac{1}{1000 \times 2 \times 10^{- 6}} = 500

∴ Z = \sqrt{{(300)}^{2} + {(900 - 500)}^{2}}

Z = 500 Ω

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