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In a series LCR circuit $R=200 \Omega$ and the voltage and the frequency of the main supply is $220 \mathrm{~V}$ and $50 \mathrm{~Hz}$ respectively. On taking out the capacitance from the circuit the current lags behind the voltage by $30^{\circ}$. On taking out the inductor from the circuit the current leads the voltage by $30^{\circ}$. The power dissipated in the LCR circuit is
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Verified Answer
The correct answer is:
$242 \mathrm{~W}$
$242 \mathrm{~W}$
The given circuit is under resonance as $X_L=X_C$ Hence power dissipated in the circuit is
$$
\mathrm{P}=\frac{\mathrm{V}^2}{\mathrm{R}}=242 \mathrm{~W}
$$
$$
\mathrm{P}=\frac{\mathrm{V}^2}{\mathrm{R}}=242 \mathrm{~W}
$$
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